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Re: Jones probability revisited |
Brian; There are two tests of significance which may be used, depending on the circumstances. If all predictions have the same probability the z-binomial test may be used. This is a standard test of significance and may be found on the VassarStats website as an interactive applet. If each prediction has a different probability the method devised By Dr Jones will be used. This procedure assigns a score to each prediction. If the prediction is correct the score is -ln(p) and if it's incorrect the score is ln(1-p), where ln is the natural log and p is the probability of success. Each prediction has an expected value which is -p*ln(p) + (1-p)*ln(1-p) and a variance which is p*(1-p)*(ln((p)*(1-p)))^2. These values are summed and the standard deviation is the square root of the variance. The final answer is (score-expected)/standard deviation. This quantity is normally distributed so the significance is determined by comparing it to a table of the normal distribution. Clear? Roger Follow Ups: ● Re: Jones probability revisited - Skywise 01:14:29 - 10/11/2013 (101039) (2) ● Re: Jones probability revisited - Skywise 16:12:09 - 10/11/2013 (101042) (1) ● Re: Jones probability revisited - Skywise 17:16:18 - 10/11/2013 (101043) (1) ● Re: Jones probability revisited - Roger Hunter 18:12:29 - 10/11/2013 (101044) (1) ● Re: Jones probability revisited - Skywise 18:29:46 - 10/11/2013 (101045) (1) ● Re: Jones probability revisited - Roger Hunter 18:40:24 - 10/11/2013 (101046) (0) ● Re: Jones probability revisited - Roger Hunter 11:04:02 - 10/11/2013 (101040) (0) |
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