Re: LOW COST EQ FORECASTING - CONCEPT -METHOD
Posted by R.Shanmugasundaram on October 21, 2001 at 16:27:15:

Hi..Billion

Part of the answer is available with our basic Geography Book. Our earth's total
circumference is around 24000 miles and so earth is rotating 1000 miles per hour.

Normally places in equator receiving 6 AM to 6 PM sunshine. i.e. 6 hours in the morning
plus 6 hours in the evening. To find out the place of a quake where is most likely to occur,
to find out the time of anomaly registered and calculate the time difference in such a way
that fixing the 12 Noon as Zero hours and multiply with 1000 miles indicates the distance
from our observatory. Suppose if you registered a reading at about 9 AM in the morning
assuming the place of occurrence at 12 noon position (Considering Sun's maximum influencing
time on the earth) 3 x 1000 = 3000 miles East from the observatory and vice-versa if you
find in the evening. So locate the week spots over the place and sit relax and wait for
the quake. OK?

SHAN
R.SHANMUGASUNDARAM
22 OCT 2001



Follow Ups:
     ● Re: LOW COST EQ FORECASTING - CONCEPT -METHOD - Billion Watts  20:08:55 - 10/21/2001  (10215)  (0)
     ● Re: LOW COST EQ FORECASTING - CONCEPT -METHOD - Billion Watts  20:08:35 - 10/21/2001  (10214)  (0)