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Quickie calc. - Re: 5.0 in Indiana?-3.5 in New Mexico |
Well, as you know: Using NEIC locations- Distance Calculation Results (from link): -Distance between 30.79S 70.96W and 38.07N 87.68W is 7859.6995 km -Distance between 12.56S 166.35E and 38.07N 87.68W is 12268.5843 km ( This calculation assumes the earth is a perfect sphere with a radius of 6378.0 km ) Circumference = 2 * PI * rad. = 40074.16 km So for Chile/Indiana the angle is: So for Santa Cruz/Indiana the angle is: The first one might be near an FFA angle and the 2nd is sorta maybe near the 107.... So for Indiana location it looks like a 50/50 proposition (as far as being actually on an FFA angle). .02 Follow Ups: ● Re: Quickie calc. - Re: 5.0 in Indiana?-3.5 in New Mexico - 2cents 03:18:37 - 6/19/2002 (16072) (1) ● 3.7 in Texas panhandle - chris in suburbia 08:49:44 - 6/19/2002 (16073) (1) ● Re: 3.7 in Texas panhandle - lowell 00:42:46 - 6/20/2002 (16079) (0) |
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