I've managed to find and incorporate into my program the formula for converting the Z score to the normal distribution (percentile) without the need to reference a look up table. YAY!!!

Roger - http://answers.yahoo.com/question/index?qid=20090224133000AAsYiTP
Note that 2.718281828459 is "e", and .39894228 is "1/sqrt(pi^2)"

So, here again are the results of my program number crunching Amit's prediction list as updated by Roger.

This is evaluating each prediction with the magnitude given:

 Total Predictions:  212
        Total Hits:  50
Standard Deviation:  10.3210039
  Normalized Score:   0.0584786
        Percentile:  52.33

And this is the same list but forcing all predictions to be 6.5 or greater rather than the exact values in the list:

 Total Predictions:  212
        Total Hits:  63
Standard Deviation:  10.3868372
  Normalized Score:  -0.3886555
        Percentile:  34.88

Brian